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CH-19-001 · Circle theorem chain with an exterior angle

A, B and C lie on a circle with centre O and radius 22 cm. B is on the major arc AC. Angle ABC = 63°. OA is extended beyond A to D.
ACBO63°D
Diagram not accurately drawn

(a) Find angle DAC. Give a reason for each stage of your working.

(b) Find the length of the minor arc AC in terms of π.

Part (a) Circle Theorems (Maths | Reason Table) & Arc Length Booklet p. 38, p. 85 & p. 86
Method
Write each calculation beside the geometric reason that justifies it
Worked Example (CH-19-001 · Part (a))
Find angle DAC. Give a reason for each stage of your working.
1)
MathsReason
∠AOC=126∘\angle AOC=126^\circAngle at the centre is twice the angle at the circumference on the same arc.
OA=OCOA=OCRadii of the same circle are equal, so triangle AOC is isosceles.
∠OAC=180−1262=27∘\angle OAC=\frac{180-126}2=27^\circThe remaining two angles in the triangle are equal.
∠DAC=180−(27)=153∘\angle DAC=180-(27)=153^\circOA and AD form a straight line.
Ans = 153°
Part (b) Circle Theorems (Maths | Reason Table) & Arc Length Booklet p. 38, p. 85 & p. 86
Method
1) Angle at centre AOC = 2 × ABC
2) Isosceles triangle OAC (radii) ⇒ OAC = (180 − AOC)/2
3) Straight line DAC = 180 − OAC
4) Arc = (AOC/
3
6
0) × 2πr
Worked Example (CH-19-001 · Part (b))
Find the length of the minor arc AC in terms of π.
1)
126360×2π×22\frac{126}{360}\times 2\pi\times 22
2)
775π\frac{77}{5}\pi cm
Ans = 775π\frac{77}{5}\pi cm